0=5t^2-14t+6

Solution for 0=5t^2-14t+6 equation:

0=5t^2-14t+6

We move all terms to the left:

0-(5t^2-14t+6)=0

We add all the numbers together, and all the variables

-(5t^2-14t+6)=0

We get rid of parentheses

-5t^2+14t-6=0

a = -5; b = 14; c = -6;
Δ = b2-4ac
Δ = 142-4·(-5)·(-6)
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{19}}{2*-5}=\frac{-14-2\sqrt{19}}{-10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{19}}{2*-5}=\frac{-14+2\sqrt{19}}{-10}
$